Can you show that [math]\displaystyle\lim_{x \to 0}\frac{1-\cos(4x)}{x^2}=8[/math] without the L'Hospital's rule? - Quora
![Proving Trigonometric Identity - cos(4x) in terms of cos(x) [cos(4x)=1-8cos^2(x)+8cos^4(x)] - YouTube Proving Trigonometric Identity - cos(4x) in terms of cos(x) [cos(4x)=1-8cos^2(x)+8cos^4(x)] - YouTube](https://i.ytimg.com/vi/49Bi35niwvs/maxresdefault.jpg)
Proving Trigonometric Identity - cos(4x) in terms of cos(x) [cos(4x)=1-8cos^2(x)+8cos^4(x)] - YouTube
How to show that 1/2 (cos4x+cos2x) =cos3xcosx by using expansions of cos (3x+x) and cos (3x-x) - Quora
![Can you help me find the following integrals (a) integration of sin 2x cos 4x dx (b)integration of cos 2x cos 4x dx (c) integration of sin 2x sin 4x dx? what Can you help me find the following integrals (a) integration of sin 2x cos 4x dx (b)integration of cos 2x cos 4x dx (c) integration of sin 2x sin 4x dx? what](https://useruploads.socratic.org/eYAVVa5QJy1Azg9Tr8qQ_int1.jpeg)
Can you help me find the following integrals (a) integration of sin 2x cos 4x dx (b)integration of cos 2x cos 4x dx (c) integration of sin 2x sin 4x dx? what
![trigonometry - ($\cos^4x$)($\sin^2x$) in terms of first power of cosine - Mathematics Stack Exchange trigonometry - ($\cos^4x$)($\sin^2x$) in terms of first power of cosine - Mathematics Stack Exchange](https://i.stack.imgur.com/QSGsf.jpg)